Question

For a concave mirrorr, if real image is formed the graph between `(1)/(u)` and `(1)/(v)` is of the form
A.
B.
C.
D.

Answer 1

Correct Answer - A
Since `(1)/(f)=+(1)/(v)+(1)/(u)implies(1)/(v)=-(1)/(u)+(1)/(f)` Putting the sign convention properly
`(1)/((-v))=(-1)/((-u))+(1)/((-f))implies(1)/(v)=-(1)/(u)+(1)/(f)`
Comparing this equation with `y=mx+c` Slope `=m=tan theta=-1impliestheta=135^(@)` or `-45^(@)` and intercept `C=+(1)/(f)`