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The spin magnetic moment of cobalt in the compound `Hg[Co(SCN)_(4)]` is

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The spin magnetic moment of cobalt in the compound `Hg[Co(SCN)_(4)]` is
A. `sqrt3`
B. `sqrt15`
C. `sqrt24`
D. `sqrt8`
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Correct Answer - b
`Hg[Co(SCN)_(4)],Co(Z=27)implies 3d^(7) 4s^(7) ,co^(2+) =3d^(7)`
Unpaired electrons `n=3`
Magnetic moment =`=sqrt(n(n+2)) =sqrt(3(3+2))=sqrt15 BM`
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