(C ) is colourless soluble solution
(C ) gives black ppt , with `H_(2)SHCI`
`rArr` (C ) is of group II
(C ) gives yellow ppt , with `KI` as well as with `K_(2)CrO_(4) rArr (c )` has `Pb^(2+)`
Thus (C) is `Pb(NO_(3))_(2)` obtained from (A),(B) on heating with `Mn^(2+)` and `HNO_(3)` gives purple colour which is due to oxidation of `Mn^(2+)` in `HMaO_(4)`(purple)
`rArr`(B) is oxidising agent
`rArr` (B) is `PbO_(2)` (blackish brown )
`rArr`(A) is doubled oxide of lead
(A ) is `Pb_(2)O_(4)` (red lead )`(2PbO.PbO_(2))`
`underset((A))(Pb_(3)O_(4)) + 4HNO_(3) rarr underset((B))(PbO_(2)) + underset((C))(2Pb(NO_(3))_(2)) + 2H_(2)O`
`underset((C))(Pb(NO_(3))_(2)) + 2KI rarr underset("Yellow")(PbI_(2)darr)`
`Pb (NO_(3))_(2) +H_(2)S rarr underset((D)black)(PbCrO_(4)darr)`
`PbO_(2) +Mn^(2+) +HNO_(3) rarr underset((E)"pink")(HMnO_(4)) +Pb^(2+)`
