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The objective lens of a compound microscope produces magnification of 10. In order to get an overall magnification of 100 when image is formed at `25cm` from the eye, the focal length of the eye lens should be
A. `4 cm`
B. `10 cm`
C. `(25)/(9)cm`
D. `9 cm`

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Correct Answer - C
`m=m_(o)xxm_(e)m=m_(o)xx(1+(D)/f_(e))`
`=10=10xx(1+(25)/(l_(e)))impliesf_(e)=(25)/(9)cm`

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