Correct Answer - C
Linear magnification `m=(-2cm)/(1 cm)=-2`
`i.e.,` image is real and inverted.
`|v|=2|u|`
Let `|u|=x` then `|v|=2x`
now `|u|+|v|=50-(-40)=90`
`:. x+2x=90`
or `x=30cm`
Hence, distance of object from the lens is `30 cm` and of object is `60cm`. therefore, lens should be located at `x=-10cm` as shown in figure.