Question

If `K_(sp)`of `M(OH)_(3)` is `1 xx 10^(-12)` then `0.001 M.M^(2+)` is precipitate in a `pH gt 9`

Answer 1

Correct Answer - T
`M(OH)_(3) `is precipitate
`[M^(3+)][OH^(Theta)]^(3) gt K_(sp) [OH^(Theta)]^(3)gt 1 xx 10^(-9)`
`[OH^(Theta)] gt 1 xx 10^(-3)`
Maximum `pOH = 3` Minimum `pH = 9`
Hence true.