Correct Answer - b,c
It must be a bicarbonate ion because first magnesium beicarbonate is formed which is soluble , then on heating , magnesium carbonate is formed which is a insoluble and forms a precipitate
`MgCI_(2) + 2NaHCO_(3) rarr underset("soluble")((Mg(HCO_(3))_(2)) + 2NaCI`
`Mg(HCO_(3))_(2) overset(Delta)(to) underset(white)(MgCO_(3) darr) + H_(2)o + co_(2)`