2x2 − 5x − 3 = 0
2x2 − 6x + x − 3 = 0
(x − 3)(2x + 1) = 0
x = 3, −21
Now,
Zeroes of the polynomial x2 + px + q are double in values to the zeroes of polynomial 2x2 − 5x − 3.
Therefore,
Zeroes of polynomial x2 + px + q will be- 6, −1
Therefore,
Sum of roots = −b/a
6 + (−1) = −p
⇒ p = -5
Product of root = c/a
6 × −1 = q
⇒ q = −6
Hence the values of p and q are -5 and −6 respectively.