Question

The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal ( for which work function is `1.65 eV`) will be
A. `4 xx 10^(10) Hz`
B. `4 xx 10^(11) Hz`
C. `4 xx 10^(14) Hz`
D. `4 xx 10^(-10) Hz`

Answer 1

Correct Answer - C
Minimum frequency : `W_(0) = hv_(0)`
`rArr v_(0) = (W_(0))/(h) = (1.65 xx 1.6 xx 10^(-19))/( 6.6 xx 10^(-34)) = 4 xx 10^(14) Hz`