Question

An `X` - ray tube with a copper target emits `Cu K_(alpha)` line of wavelength `1.50 Å`. What should be the minimum voltage through which electrons are to be accelarated to produce this wavelength of `X` - rays ?
`( h = 6.63 xx 10^(-34) J - sec , c = 3 xx 10^(8) m//s)`

Answer 1

Correct Answer - A
`eV = (hc)/(lambda) = (6.63 xx 10^(-34) xx 3 xx 10^(8))/(1.5 xx 10^(-10))`
`rArr V = (6.63 xx 10^(-34) xx 3 xx 10^(8))/(1.5 xx 10^(-10)) = 8280 "Volt"`.