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The photoelectric threshold wavelength for potassium (work function being `2 eV`) is
A. `310 nm`
B. `620 nm`
C. `1200 nm`
D. `2100 nm`

1 Answer

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Correct Answer - B
`lambda = (12375)/(W_(0)) = (12375)/(2) = 6187.5 Å = 620 nm`

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