Correct Answer - D
For first line in Lyman series `lambda_(L_(1)) = (4)/(3R) ………(i)`
For first line in Balmer series `lambda_(B_(1)) = (36)/(5R)……..(ii)`
From equations (i) and (ii)
`lambda_(B_(1))/(lambda_(L_(1))) = (27)/(5) rArr lambda_(B_(1)) = (27)/(5) lambda`