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The first line in the Lyman series has wavelength `lambda`. The wavelegnth of the first line in Balmer series is
A. `(2)/(9)lambda`
B. `(9)/(2)lambda`
C. `(5)/(27)lambda`
D. `(27)/(5)lambda`

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Correct Answer - D
For first line in Lyman series `lambda_(L_(1)) = (4)/(3R) ………(i)`
For first line in Balmer series `lambda_(B_(1)) = (36)/(5R)……..(ii)`
From equations (i) and (ii)
`lambda_(B_(1))/(lambda_(L_(1))) = (27)/(5) rArr lambda_(B_(1)) = (27)/(5) lambda`

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