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Energy of the electron in `nth` orbit of hydrogen atom is given by `E_(n) =-(13.6)/(n^(2))eV`. The amount of energy needed to transfer electron from first orbit to third orbit is
A. `13.6 eV`
B. `3.4 eV`
C. `12.09 eV`
D. `1.51 eV`

1 Answer

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Best answer
Correct Answer - C
For `n = 1,E_(1) =- (13.6)/((1)^(2)) =- 13.6 eV`
and for `n=3, E_(3) =- (13.6)/((3)^(2)) =- 1.51 eV`
So required enegry
`= E_(3) - E_(1) =- 1.51 -(-13.6) = 12.09 eV`

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