Correct Answer - D
The point P lies on the axial line of magnet `N_1S_1` at distance `r_1(=1m)` and on equatorial line of magnet `N_2S_2` at distance `r_2(=1m)`, figure.
`:. B_1=(mu_0)/(4pi)(2M_1)/(r_1^3)=10^-7xx(2xx2)/(1^3)=4xx10^-7T`
`B_2=(mu_0)/(4pi)(M_2)/(r_2^3)=10^-7xx(2)/(1^3)=2xx10^-7T`
Resultant magnetic field at P,
`B=sqrt(B_1^2+B_2^2)=sqrt((4xx10^-7)^2+(2xx10^-7)^2)`
`=2sqrt5xx10^-7T`