Question

An average induced e.m.f. of 0.4 V appears in a coil when current in it is changed from 10 A in one direction to 10 A in opposite direction in 0.40 second. Find the coefficient of self induction of the coil.

Answer 1

Here, `e = 0.4 V`,
`dI = 10 - (-10) = 20 A, dt = 0.40 s , L = ?`
From `e = L d I//dt`,
`L = (e dt)/(dt) = (0.4 xx 0.4)/(20) = 8 xx 10^(-3) H`