Question

A capacitor of capacitance `10 muF` is connected to an oscillator giving an output voltage `epsilon = (10 V) sin omegat`. Find the peak currents in the circuit for `omega = 10 s^(-1), 100 s^(-1), 500 s^(-1), 1000 s^(-1)`.

Answer 1

Here, `C = 10 mu F = 10 xx 10^(-6)`
`= 10^(5) F`
As `E = 10 sin omega t :. E_(0) = 10 V, omega = 10 rad//s`
`I_(0) = (E_(0))/(X_(C )) = (E_(0))/(1//omega C) = E_(0) omega C`
`= 10 xx 10 xx 10^(-5) = 10^(-3) A = 1 mA`