Question

A coil of inductance 0.4 mH is connected to a capacitor of capacitance 400 pF. To what wavelength is this circuit truned ?

Answer 1

Here, `L = 0.4 mH = 0.4 xx 10^(-3) H`
`C = 400 pF = 400 xx 10^(-12) F = 4 xx 10^(-10) F, lambda = ?`
`v = (1)/( 2pi sqrt(LC)) = (1)/(2 xx 3.14 sqrt(0.4 xx 10^(-3) xx 4 xx 10^(-10))`
`v = (10^(7))/(6.28 xx 4)` hertz
If v is velocityof em waves, then
`lambda = (upsilon)/(v) = (3 xx 10^(8))/(10^(7) // 6.28 xx 4) = 6.28 xx 4 xx 3 xx 10`
`= 753.6 m`