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If `alpha=0.98` and current through emitter `i_(e)=20 mA`, the value of `beta` is

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If `alpha=0.98` and current through emitter `i_(e)=20 mA`, the value of `beta` is
A. `4.9`
B. `49`
C. `96`
D. `9.6`
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1 Answer

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Correct Answer - B
`beta=(alpha)/(1-alpha)=0.98/(1-0.98)=49`.
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