Question

A `npn` transistor is connected in common emitter configuration in a given amplifier. A load resistance of `800 Omega` is connected in the collector circuit and the voltage drop across it is `0.8 V`. If the current amplification factor the voltage gain and the power gain of the amplifies will respectively be:
A. `4,3.84`
B. `3.69,3.84`
C. `4,4`
D. `4,3.69`

Answer 1

Correct Answer - A
Voltage gain =[current gain][resistance gain]
Given current gain `=alpha=0.96`
Voltage gain for common base configuration
`A_(v)=alpha.(R_(L))/(R_(p))=0.96xx800/192=4`
Power gain for common base configuration `P_(v)=A_(v)alpha=4xx0.96=3.84`