Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
248 views
in Physics by (72.7k points)
closed by
A coil of 0.01 henry inductance and 1 ohm resistance is connected to 200 volt, 50 Hz ac supply. Find the impedance of the circuit and time lag between max. alternating voltage and current.

1 Answer

+1 vote
by (118k points)
selected by
 
Best answer
Here, `L = 0.01 H, R = 1 Omega, E_(v) = 200 V, v = 50 Hz, Z = ?, Delta t = ?`
`X_(L) = omega L = 2 pi v L = 2 xx 3.14 xx 50 xx 0.01 = 3.14 Omega`
`Z = sqrt(R^(2) + X_(L)^(2)) = sqrt(1^(2) + (3.14)^(2)) = sqrt(10.86) = 3.3 ohm`
`tan phi = (omega L)/(R ) = 3.14`
`phi = tan^(-1) (3.14) = 72^(@) = 72 xx (pi)/(180) rad`
Time lag, `Delta t = (phi)/(omega) = (72 xx pi)/(180 xx 2 pi xx 50) = (1)/(250) sec`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...