Question

The self inductance of an inductance coil having 100 turns 20 20 mH. Calculate the magnetic flux through the cross section of the coil corresponding to a current of 4 milliampere. Also, find the total flux

Answer 1

Here, `n = 100, L = 20 mH = 20 xx 10^(-) H`
`i= 4 mA = 4 xx 10^(-3) A`
Magnetic flux through the cross section of coil
`= Li = 20 xx 10^(-3) xx 4 10^(-3)`
`= 8 xx 10^(-5) Wb`