Question

A 100 ohm iron is connected to a 110 V - 60 hertz wall plug. What is (1) peak pot. Diff. (ii) average potential diff. over a half cycle and (iii) rms current ?

Answer 1

Here, `R = 100 ohm, E_(v) = 110 V, v = 60 hz`
`E_(0) = sqrt2 E_(v) = 1.414 xx 110 = 155.5 V`,
`E_(m) = (2 E_(0))/(pi) = (2 xx 155.5)/(3.14) = 99.1 V`
`I_(v) = (E_(v))/(R ) = (110)/(100) = 1.1 A`