Here, `n_(P) = 100, K = 100, E_(P) = 220 V`,
`P_(i) = 1100 W`
(i) From `K = (n_(s))/(n_(P))`
(ii) From `P_(i) = E_(P) I_(P)`
`I_(P) = (P_(i))/(E_(P)) = (1100)/(250) = 5 A`
`(E_(s))/(E_(p)) = (n_(s))/(n_(P)) = K`
(iv) `(I_(s))/(I_(P)) = (n_(P))/(n_(s)) = (1)/(K)`
`I_(s) = (I_(P))/(K) = (5)/(100) = 0.05 A`
(v) Power in secondary `= P_(0) = P_(i) = 1100 W`