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The transfer ration of a transistor is `50`. The input resistance of the transistor when used in the common -emitter configuration is `1 kOmega`. The peak value for an `A.C.` input voltage of `0.01 V` peak is
A. `0.25 muA`
B. `0.01 muA`
C. `500 muA`
D. `100 muA`

1 Answer

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Best answer
Correct Answer - c
Input current `=(V_(i))/(R_(i))=(0.01)/(10^(3))= 10^(-5)A`
Output collector current `=Bxx "input current"`
`= 50xx10^(-5)`
`=500A`

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