Correct Answer - B
(b) When one charged and other uncharged conducting spheres are in contact then charge on each sphere is half the charge on first charged sphere.
When both the spheres are placed in contact with each other, the charge on each,
`q_(1) = q_(2) = q = (10 + 0)/(2) muC = 5 mu C`
Surface charge density is given by, `sigma = (q)/(4 pi r)`
Hence, `sigma_(1) = (q_(1))/(4 pi r_(1)^(2))` and `sigma_(2) = (q_(2))/(4 pi r_(2)^(2))`
`implies (sigma_(1))/(sigma_(2)) = (q_(1))/(4 pi r_(1)^(2)) (4 pi_(2)^(2))/(q_(2)) = (5 xx (20)^(2))/((10)^(2) xx 5) = (4)/(1)`