Question

How many electrons per sec pass through a cross-section of a copper wire carrying `10^(-15)` ampere?

Answer 1

Current strength `(i) = ("Total charge")/("Time (in sec.)")=(C)/(s)`
Also Total charge = Number of electron `xx` Change on one electron
`:. i = ("Number of electron" xx "Charge on one electron")/("Time (in sec.)")`
`:.` No. of electron passed in `1` sec.
`= (i)/("Charge on 1 electron") = (10^(-15))/(1.6 xx 10^(-19)) = 6250`