The resistance of a conductivity cell filled with `0.1 M KCl` solution is `100 Omega`. If `R` of the same cell when filled with `0.02 M KCl` solution is `520 Omega`, calculate the conductivity and molar conductivity of `0.02 M KCl` solution. The conductivity of `0.1 M KCl `solution is `1.29 S m^(-1)`.
A. `124 xx 10^(-4) S m^(2) mol^(-1)`
B. `1240 xx 10^(-4) S m^(2) mol^(-1)`
C. `1.24 xx 10^(-4) S m^(2) mol^(-1)`
D. `12.4 xx 10^(-4) S m^(2) mol^(-1)`