Question

Calculate the boiling point of a solution containing `0.61 g` of benzoic acid in `50 g` of carbon disulphide assuming `84%` dimerization of the acid. The boiling point and `K_(b)` of `CS_(2)` are `46.2^(@)C` and `2.3 kg mol^(-1)`.

Answer 1

`Delta T = (1000 xx K_(b) xx w)/( m xx W)`
`Delta T_(N) = (1000 xx 2.3 xx 0.61)/(122 xx 50)`
`(m`.wt. of `C_(6)H_(5)COOH = 122`)
`Delta T_(N) = 0.23`
`Delta T_(exp.) = Delta T_(N) (1-alpha+(alpha)/(n)) = 0.23 xx (1-0.84+(0.84)/(2))`
`= 0.23 xx (1-(0.84)/(2)) = 0.1334`
B. pt. `= 46.2 + 0.1334 = 46.3334^(@)C`