Question

A `0.001` molal solution of `[Pt(NH_(3))_(4)Cl_(4)]` in water had freezing point depression of `0.0054^(@)C`. If `K_(f)` for water is `1.80`, calculating the number f `Cl^(-)` ions furnished.

Answer 1

Correct Answer - 2
`because Delta T = iK_(f)m`
`:. 0.0054 = i xx 1.80 xx 0.001 :. i=3`
`:.` The formula of complex is `[Pt(NH_(3))_(4)Cl_(2)]Cl_(2)`
Hence furnishes `2Cl^(-)` ions
i.e., `[Pt(NH_(3))_(4)]Cl_(2)]^(2+)` and `2Cl^(-)`