Question

For the reaction `2N_(2)O_(5)rarr 4NO_(2)+O_(2)`, if rate formation of `O_(2) is 16 g//hr`, then rate of decomposition of `N_(2)O_(5)` and rate of formation of `NO_(2)` respectively is:
A. `54 g//hr and 46 g//hr`
B. `32 g//hr and 64 g//hr`
C. `108 g//hr and 92 g//hr`
D. None of these

Answer 1

Correct Answer - c
`(d[O_(2)])/(dt)=16 g//hr=16/32 mol//hr`
`(d[NO_(2)])/(dt)=(4d[O_(2)])/(dt)=4xx16/32=2 mol//hr`
`=2xx46=92 g//hr`
`(-d[N_(2)O_(5)])/(dt)=(2d[O_(2)])/(dt)=2xx16/32=1 mol//hr`
`=1xx108=108 g//hr`