Here, the point `P` on the right of the lens acts as a virtual object, `:. U = 12 cm, v = ?`
As `(1)/(v) - (1)/(u) = (1)/(f) :. (1)/(v) - (1)/(12) = (1)/(20)`
`(1)/(v) = (1)/(20) + (1)/(12) = (3 + 5)/(60) = (8)/(60)`
`v = 60//8 = 7.5 cm`
Image is at `7.5 cm` to the right of the lens where the beam converges.
(b) `f = - 16cm, u = 12 cm, :. (1)/(v) = (1)/(f) + (1)/(u) = -(1)/(16) + (1)/(12) = (-3 + 4)/(48) = (1)/(48)`
`v = 48 cm`
Hence, image is at `48 cm` to the right of the lens, where the beam would converge.