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A reflecting type telescope has a concave reflector of radius of curvature `120 cm`. Calculate the focal length of eye piece to secure a magnification of `15`.

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Correct Answer - `4 cm`
Here, `R = 120 cm, f_(e) = ? m = 15`
`f_(0) = R//2 = 120//2 = 60 cm`
From `m = (f_(0))/(f_(e))`
`f_(e) = (f_(0))/(m) = (60)/(15) = 4 cm`

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