From the previous problem, if the components are `lambda,lambda+-Delta lambda`, then
`(lambda)/(Delta lambda)=(2pi ħc)/(mu_(B)B lambda)`
For resolution `(lambda)/(Delta lambda)leR=(lambda)/(delta lambda)` of the instrument.
Thus `(2 pi ħc)/(mu_(B)B lambda)leR or Bge(2pi ħc)/(mu_(B)lambdaR)`
Hence the minimum megnetic induction is
`B_(m in)=(2pi ħc)/(mu_(B)lambdaR)= 4kG= 0.4T`