Correct Answer - A::B::C
Here, `f_(0) = 20 m and f_(e) = 2 cm = 0.02 m`.
In normal adjustment, length of telescope tube `L = f_(0) + f_(e) = 20.02 m`
Magnification `= (f_(0))/(f_(e)) = (20)/(0.02) = 1000`.
The image formed is inverted (w.r.t. the object). Choice (a), (b) and (c ) are correct.