A proton and an `alpha`-particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths `lambd

As, `lambda=h/(sqrt(2mqV)) :. lambda prop 1/(sqrt(mq)) :. (lambda_(p))/(lambda_(alpha)) =(sqrt(m_(alpha)q_(alpha)))/(sqrt(m_(p)q_(p)))=(sqrt(4m_(p)xx2e))/(sqrt(m_(p)xxe))=sqrt8=2sqrt2`

A proton and an `alpha`-particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths `lambda_(p) and lambda_(a)`

Please log in or register to add a comment.

1 Answer

Please log in or register to add a comment.

Find MCQs & Mock Test

Related questions

Categories