Calculate the de-Broglie wavelength of an electron of kinetic energy 100 eV. Given `m_(e)=9.1xx10^(-31)kg, h=6.62xx10^(-34)Js`.

Correct Answer - `1.227 Å`
`K=100eV =100xx1.6xx10^(-19)J=1.6xx10^(-17)J`
`lambda=h/(sqrt(2mK))=(6.62xx10^(-34))/(sqrt(2xx(9.1xx10^(-31))xx1.6xx10^(-17)))`
`=1.227xx10^(-10)m=1.227Å`

Calculate the de-Broglie wavelength of an electron of kinetic energy 100 eV. Given `m_(e)=9.1xx10^(-31)kg, h=6.62xx10^(-34)Js`.

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