Correct Answer - B
Molarity =`1M=1moL^(-1)`
`1000`mL of solution has glucose =`180g`
`(1000xx1.2)g` of solution has glusose =`180g`
`:.` Solute`(w_(1))=180g`
solution =`1200g`
solvent ,`H_(2)O(w_(2))=1200-180=1020g`
`:. DeltaT_(b)=(1000K_(b)w_(1))/(m_(1)w_(2))`
`(1000xxk_(b)xx180)/(180xx1020)=0.98K_(b)`