Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
108 views
in Chemistry by (90.3k points)
closed by
Elevation in boiling point of a molar `(1M)`glucose solution`(d=1.2 g ml_(-1))` is
A. `1.34K_(b)`
B. `0.98K_(b)`
C. `2.40K_(b)`
D. `K_(b)`

1 Answer

0 votes
by (91.1k points)
selected by
 
Best answer
Correct Answer - B
Molarity =`1M=1moL^(-1)`
`1000`mL of solution has glucose =`180g`
`(1000xx1.2)g` of solution has glusose =`180g`
`:.` Solute`(w_(1))=180g`
solution =`1200g`
solvent ,`H_(2)O(w_(2))=1200-180=1020g`
`:. DeltaT_(b)=(1000K_(b)w_(1))/(m_(1)w_(2))`
`(1000xxk_(b)xx180)/(180xx1020)=0.98K_(b)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...