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Aqueous solution of barium phosphate which is `100%`ionised has `DeltaT_(f)//K_(f)`as 0.05.Hence ,given solution is
A. 0.01 molal
B. 0.02 molal
C. 0.04 molal
D. 0.05 molal

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Best answer
Correct Answer - A
`Ba_(3)(PO_(4))_(2)hArr 3Ba^(2+)+2PO_(4)^(3-)`
value of i=`5(100%ionised)`
so`DeltaT_(f)=ik_(f)m`
so m =`(cancel(O)T_(f))/(ik_(f))=(0.05)/(5)=0.01`

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