Question

Assuming that in a star, three alpha particle join in a single fusion reaction to form `._(6)C^(12)` nucleus. Calculate the energy released in this reaction. Given mass of `._(2)He^(4)` is 4.002604 a.m.u. and that of `._(6)C^(12)` is 12 a.m.u. Take 1a.m.u. =931MeV.

Answer 1

Correct Answer - 7.27MeV
Mass defect, `Deltam=3xx4.002604-12`
`=12.007812-12=0.007812 a.m.u.`
`:.` Energy released `=0.007812xx931MeV`
`=7.27MeV`