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In a n-p-n transister circuit the collector current is `9 mA`. If `90%` of the electrons emitted reach the collector, find emitter current and base current

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Here, `I_(c)=9mA=90/100I_(e)=9/10Ie`
or `I_(e)=9xx10/9=10mA`
So `I_b =I_e -I_(c) =10-9=1mA`

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