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Xenon crystallises in face - centered cubic , and the edge of the unit cell is 620 pm .The radius of a xenon atom is
A. `438.5` pm
B. `219.25` pm
C. `536.94` pm
D. `265.5` pm

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Correct Answer - b
For fcc lattice
`4r = sqrt(2)a ` where `a = 620` pm
or , `r = (1)/(2sqrt(2)) xx a`
`= (1)/(2sqrt(2)) xx 620` pm
`= 219.20` pm

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