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In electorlysis of an aqueous solution of sodimum sulphate, `2.4 L` of oxygen at `STP` was liberated at anonde. The volume of hudrogen at `STP` liberated at cathode would be .
A. ` 1.2 L`
B. ` 2.4 L`
C. ` 2.6 L`
D. ` 4 .8 L`

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Correct Answer - D
AT cathode , At anode
`As^+ +e rarr NaH_2 rarr2H^+ +2e^-`
So 1 mole has ` 2.4`
So `2` mole has ` =2.4 xx 2 = 4.8`.

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