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How many `kJ` of energy is spent when a currebnt of (4) amp passes for `200` second under a potential of `115 V` ?
A. ` 52 k J`
B. `72 k J`
C. ` 82 k J`
D. `92 k J`

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Correct Answer - D
` Delta G=- nFE=-QE`
`=- 4 xx200 xx 115 xx 10^(-3) h J`
`Delta G=- 92 kJ`

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