Question

The correct representation of Nernst`s equaion is .
A. `E_(M^(n+) //M) = E_( M^(n+)//M)^@ + n/( 0.591) log (M^(n+))`
B. `E_(M^(n+)) //M) = E_(M^(n+)//M)^@ + n/( 0.591) log (M^(n+))`
C. `E_(M^(n+) //M) = E_(M^(n+)//M)^@ + n/( 0.591) log (M^(n+))`
D. None of the above

Answer 1

Correct Answer - C
` E=E^@ - (RT)/(nF) In 1/([M^(n+)]) , E=E^@ + (RT)/(nF) In [M^(n+)]`
`E=E^@ + ( 2.303 RT)/(nF) log [M^(n+)]`
Substituting the value of `R,T (298 K)` and `F` we get
`E=E^@ + ( 0.591)/n log (M^(n+))`.