Question

The width of depletion region in a P-N junction diode is 500 nm and an intense electric field of `5xx10^(5)Vm^(-1)` is also found to exit init. Determine the height of the potential barrier. Also calculate the kinetic energy which a conduction electron must have inorder to diffuse from the n-side to p-side.

Answer 1

`V=Ed=(5xx10^(5))xx(500xx10^(-9))=0.25V`
Max. K.E. of an electron to cross the potential barrier
`V=eV=1.6xx10^(-19)xx0.25J`
`=(1.6xx10^(-19)xx0.25)/(1.6xx10^(-19))eV=0.25 eV`