Question

In a zero-order reaction for every `10^(@)` rise of temperature, the rate is doubled. If the temperature is increased from `10^(@)C` to `100^(@)C`, the rate of the reaction will become
A. `64` times
B. `512` times
C. `256` times
D. `128` times

Answer 1

Correct Answer - B
`(r + (r +100))/(r_(t)) = 2` for each `10^(@)` rise in temperature
`:. (r_(100))/(r_(10)) = (2)^(9) = 512`