Correct Answer - A
For a first order reaction, `K = (2.303)/(t) "log"(a)/(a-x)`, where a is initial concentration, and x is the amount reatced in time `t`.
For hlaf-life `x = a//2, t = t_(1//2)`
`K = (2.303)/(K)"log"(a)/(a-a//2)`
`t_(1//2) = (2.303)/(K)log2 = (0.693)/(K)`.