Question

Find the ratio between the energy stored in `5uF` capacitor to the `4muF` capacitor in the given circuit in steady state.

Answer 1

Correct Answer - `0.8`
`{:(I =(2)/(5+4)amp,,rArr,,I=(2)/(9)Amp):}`
`V_(AC) = 5xx (2)/(9)"volt" = (10)/(9)"volt"`

`V_(DB) = 4xx(2)/(9)"volt" = (8)/(9)"volt"`
`(U_(5muF))/(U_(4muF)) =((1)/(2)xx5((8)/(9))^(2))/((1)/(2)xx4xx((10)/(9))^(2))=0.8`