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The ratio of power dissipated respectively in `R` and `3R`, as shown is:

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The ratio of power dissipated respectively in `R` and `3R`, as shown is:
image
A. `9`
B. `27//4`
C. `4//9`
D. `4//27`
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Correct Answer - D
image
`I_(R)=(2R)/(3R)xxI=(2I)/3 & H=I^(2)R`
`(H_(R))/(H_(3R))=((I_(R))/(I_(3R)))^(2)xxR/(3R)=(2/3)^(2)xx1/3=4/27`
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