Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
103 views
in Physics by (97.8k points)
closed by
Resistances `R_(1)` and `R_(2)` each 60 are connected in series as shown in figure. The potential difference between `A` and `B` is kept 120 volt. Then what will be tha reading of voltmeter connected between thapoint `C` and `D` if resistance of voltmeter is `120 Omega` ?
image
A. `48 V`
B. `24 V`
C. `40 V`
D. None

1 Answer

0 votes
by (98.2k points)
selected by
 
Best answer
Correct Answer - A
`I=120/(60+60||120)=1.2` Amp
Reading of voltmeter `1.2xx(60||120)`
image
`=1.2xx40=48` volt

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...